In Java, if a method receives an int parameter and prints the parameter value after applying the pre-increment operator (++), what value is printed first?

In Java, if a method receives an int parameter and prints the parameter value after applying the pre-increment operator (++), what value is printed first?

• A. 6
• B. 5
• C. 55
• D. 65

Answer: (A)

Pre-increment (++x) increases the value before it’s used. So printing ++param shows the parameter’s value after it has been incremented. If the method receives 5, applying ++ results in 6, which is what gets printed. The parameter here is a primitive, so the increment affects only this local copy, not the caller’s variable. That’s why 6 is printed in this scenario.

Pre-increment (++x) increases the value before it’s used. So printing ++param shows the parameter’s value after it has been incremented. If the method receives 5, applying ++ results in 6, which is what gets printed. The parameter here is a primitive, so the increment affects only this local copy, not the caller’s variable. That’s why 6 is printed in this scenario.